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Private · U.S. Army

Thomas Sullivan

Private Thomas Sullivan, Army, received the Medal of Honor for actions on October 20, 1869 in Chiricahua Mountains, Arizona Territory during the Indian Campaigns.

Private Thomas Sullivan was a soldier in the U.S. Army who received the Medal of Honor for his actions on October 20, 1869 in Chiricahua Mountains, Arizona Territory during the Indian Campaigns. At the time he was serving with Company G, 1st U.S. Cavalry. Sullivan was about 22 years old.

32 other service members also received the Medal of Honor for actions on the same day. The medal was presented on December 20, 1869.

Sullivan was born in 1847 in Covington, Kenton County, Kentucky. His Medal of Honor is credited to Cincinnati, Hamilton County, Ohio.

Sullivan is one of 426 Medal of Honor recipients from the Indian Campaigns and one of 256 credited to Ohio.

Official Medal of Honor citation

Gallantry in action against Indians concealed in a ravine.

Citation text: U.S. Government, public domain.

Places

  • Born: Covington — map

Veteran resources, cemeteries and meeting places in Ohio →

Timeline

  1. 1847
    Born in Covington, Kenton County, Kentucky
  2. October 20, 1869
    Act of valor — Chiricahua Mountains, Arizona Territory
    Age about 22. Company G, 1st U.S. Cavalry
  3. December 20, 1869
    Medal of Honor presented

Biography

Thomas Sullivan was a United States Army soldier who was awarded the Medal of Honor for his actions at the Chiricahua Mountains.

From the Wikipedia article “Thomas Sullivan (Medal of Honor, 1869)”, licensed under CC BY-SA 4.0. Read the full article →

Also honored for actions on October 20, 1869

See all 33 recipients for October 20, 1869 →

More Indian Campaigns recipients from Ohio

Sources. Service and award details compiled from the recipient record of the Congressional Medal of Honor Society, Wikidata and Wikipedia. The narrative summary is generated from these records. Spotted an error? Send a correction.