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Private · U.S. Army

John L. Donahue

Private John L. Donahue, Army, received the Medal of Honor for actions on October 20, 1869 in Chiricahua Mountains, Arizona Territory during the Indian Campaigns.

Private John L. Donahue was a soldier in the U.S. Army who received the Medal of Honor for his actions on October 20, 1869 in Chiricahua Mountains, Arizona Territory during the Indian Campaigns. At the time he was serving with Company G, 8th U.S. Cavalry. Donahue was about 22 years old.

32 other service members also received the Medal of Honor for actions on the same day. The medal was presented on February 14, 1870.

Donahue was born in 1847 in Baltimore County, Maryland. His Medal of Honor is credited to Baltimore, Baltimore County, Maryland. Donahue died on March 16, 1900, at the age of about 53. He is buried at Arlington National Cemetery in Arlington, Virginia. Records also list him as Donohue, John L..

Donahue is one of 426 Medal of Honor recipients from the Indian Campaigns and one of 85 credited to Maryland.

Official Medal of Honor citation

Gallantry in action.

Citation text: U.S. Government, public domain.

Timeline

  1. 1847
    Born in Baltimore County, Maryland
  2. October 20, 1869
    Act of valor — Chiricahua Mountains, Arizona Territory
    Age about 22. Company G, 8th U.S. Cavalry
  3. February 14, 1870
    Medal of Honor presented
  4. March 16, 1900
    Died
    Age about 53.
  5. Resting place
    Arlington National Cemetery
    Arlington, Virginia

Also honored for actions on October 20, 1869

See all 33 recipients for October 20, 1869 →

More Indian Campaigns recipients from Maryland

Sources. Service and award details compiled from the recipient record of the Congressional Medal of Honor Society. The narrative summary is generated from these records. Spotted an error? Send a correction.