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Sergeant · U.S. Army

William de Armond

Sergeant William de Armond, Army, received the Medal of Honor posthumously for actions between September 9 and 11, 1874 in Upper Washita, Texas during the Indian Campaigns.

Sergeant William de Armond, a soldier in the U.S. Army, was awarded the Medal of Honor posthumously for gallantry between September 9 and 11, 1874 in Upper Washita, Texas during the Indian Campaigns. At the time he was serving with Company I, 5th U.S. Infantry. de Armond was about 36 years old.

de Armond was killed in the action for which his medal was awarded. 11 other service members also received the Medal of Honor for actions on the same day. The medal was presented on April 23, 1875.

de Armond was born in 1838 in Butler County, Ohio. His Medal of Honor is credited to New York, New York. He is buried at San Antonio National Cemetery in San Antonio, Texas.

de Armond is one of 426 Medal of Honor recipients from the Indian Campaigns and one of 678 credited to New York.

Official Medal of Honor citation

Gallantry in action.

Citation text: U.S. Government, public domain.

Wounds and death in action

  • Killed in action during the act for which the medal was awarded (September 9, 1874).
  • Age at death: about 36
  • Resting place: San Antonio National Cemetery

Timeline

  1. 1838
    Born in Butler County, Ohio
  2. September 9 - 11, 1874
    Act of valor — Upper Washita, Texas
    Age about 36. Company I, 5th U.S. Infantry Killed in action.
  3. April 23, 1875
    Medal of Honor presented posthumously
  4. Resting place
    San Antonio National Cemetery
    San Antonio, Texas

Also honored for actions on September 9 - 11, 1874

Same unit

More Indian Campaigns recipients from New York

Sources. Service and award details compiled from the recipient record of the Congressional Medal of Honor Society. The narrative summary is generated from these records. Spotted an error? Send a correction.