Serving as a soldier in the U.S. Army, Sergeant Henry J. Hyde received the Medal of Honor for his actions in 1872 in Arizona during the Indian Campaigns. At the time he was serving with Company M, 1st U.S. Cavalry. Hyde was about 26 years old.
The medal was presented on August 12, 1875, 3 years after the action.
Hyde was born on February 11, 1846 in Bangor, Penobscot County, Maine. His Medal of Honor is credited to New York, New York. Hyde died on July 25, 1893 in Marion, Indiana, at the age of 47. He is buried at Marion National Cemetery in Marion, Indiana.
Hyde is one of 426 Medal of Honor recipients from the Indian Campaigns and one of 678 credited to New York.
Official Medal of Honor citation
Gallant conduct during campaigns and engagements with Apaches.
Citation text: U.S. Government, public domain.
Battles and campaigns
Also served in: American Indian Wars.
Places
- Born: Bangor — map
Veteran resources, cemeteries and meeting places in New York →
Timeline
- February 11, 1846Born in Bangor, Penobscot County, Maine
- 1872Act of valor — ArizonaAge about 26. Company M, 1st U.S. Cavalry
- August 12, 1875Medal of Honor presented
- July 25, 1893Died in Marion, IndianaAge 47.
- Resting placeMarion National CemeteryMarion, Indiana
Biography
Henry J. Hyde (February 11, 1846 – July 25, 1893) was a United States Army Sergeant during the Indian Wars who received the Medal of Honor on August 12, 1875, for service during the winter of 1872–73. Hyde joined the army from New York City in August 1869, and was discharged in November 1884.
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