Sergeant William Wallace, a soldier in the U.S. Army, received the Medal of Honor for gallantry on October 21, 1876 at Cedar Creek, etc., Montana during the Indian Campaigns. At the time he was serving with Company C, 5th U.S. Infantry. Wallace was 28 years old.
29 other service members also received the Medal of Honor for actions on the same day. The medal was presented on July 18, 1877.
Wallace was born on October 31, 1847 in County Donegal, Ireland — one of 258 recipients born in Ireland. His Medal of Honor is credited to New York, New York. Wallace died on January 9, 1928 in Walnut, Kansas, at the age of 80. He is buried at Walnut Cemetery in Walnut, Kansas. Records also list him as Wallace, John A..
Wallace is one of 426 Medal of Honor recipients from the Indian Campaigns and one of 678 credited to New York.
Official Medal of Honor citation
Gallantry in action.
Citation text: U.S. Government, public domain.
Timeline
- October 31, 1847Born in County Donegal, Ireland
- October 21, 1876Act of valor — Cedar Creek, etc., MontanaAge 28. Company C, 5th U.S. Infantry
- July 18, 1877Medal of Honor presented
- January 9, 1928Died in Walnut, KansasAge 80.
- Resting placeWalnut CemeteryWalnut, Kansas
